7
Jan
2021
Question of the Day By Maths Grinds
//
Comments0
Prove that $e^a (b-a) < e^b – e^a < e^b(b-a)$ for all $a<b$ in $\mathbb{R}$.
My Journal
Maths Grinds
Prove that $e^a (b-a) < e^b – e^a < e^b(b-a)$ for all $a<b$ in $\mathbb{R}$.